The question is — does two pair beat a straight? The answer in this case is no. Bridge card games. How many combinations are there in poker?
How many ways can you get two pairs in poker? Can you have 3 pairs poker? What is the strongest poker hand? Who wins in poker if both have 2 pair? What is the probability of getting two pairs in poker? Do 2 pairs beat 3 2 pairs? Why does three pair not exist? How many possible hand combinations are there in poker? How many cards are in a poker hand? What are the chances of winning a pair of poker cards? How many hand combinations are in a deck of cards?
How many combinations of Aces and kings are there in poker? How many pairs of poker hands are possible? Which two pair is higher in poker? But technically, we want to know the probability of an exact starting hand being dealt, e. Js7h, suits included given that poker has the flop, turn, and river streets, to play or run out. Js7h is one single combo, the chance of being dealt this is therefore 1 in But the chance of being dealt any combo of J7 off-suit is 16 in , because there are 16 combinations of J7o.
To illustrate with the suited cards - there are four suits - spades, clubs, hearts, diamonds. The probability of being dealt Jd7d J7 of diamonds is the same as being dealt Js7h, 1 in But the probability of being dealt J7 'suited' isn't 16 in , like it is with J7 off suit, instead it is 4 in There are a total of 16 combinations of AK or J7. Four of those combinations are suited, 12 are un-suited.
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Learn more. Starting hands probability Ask Question. Asked 8 years, 8 months ago. Active 1 year, 10 months ago. Viewed 20k times. The following is a passage from Wikipedia on starting hands probability: The 1, starting hands can be reduced for purposes of determining the probability of starting hands for Hold 'em—since suits have no relative value in poker, many of these hands are identical in value before the flop.
Improve this question. Theo Theo 3 3 gold badges 10 10 silver badges 20 20 bronze badges. Add a comment. Counting combinations. The number of combinations of n objects taken r at a time is. In summary, we use the combination formula to count a the number of possible five-card hands and b the number of ways a particular type of hand can be dealt.
To find probability, we divide the latter by the former. The number of ways to produce four of a kind Num 4 is equal to the product of the number of ways to make each independent choice. The probability of being dealt four of a kind is 0. On average, four of a kind is dealt one time in every 4, deals. The number of ways to produce full house Num fh is equal to the product of the number of ways to make each independent choice.
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